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With the center of the circle 16 feet (40-24) below ground, I made a rough estimate of the answer.
I visited the web site mentioned by the person who started this thread. The photos of a Quonset hut reveal that they are about a third of a circle, not a semi-circle. What I mean is that the center of the circle is below the ground about ten feet.
It looks like the Wiki's designation of the quonset as a smeicircle is incorrect--it's not limited to being a half-circle only. Otherwise, the dimensions of the original quonsets that they published would be incorrect. So, it must be a segment of a circle, and we need to find the radius of that circle.
Isn't the width the diameter and the height the radius? And if so, wouldn't height be width/2?
A quonset hut would be half of a right solid cylinder. Length is given as 205 feet. Width is given as 80 feet, and height 24 feet. But if the width is 80 feet, the height would have to be 25.46479 feet. That is obtained by dividing 80 by pi.
Please help me figure out the total volume of a quonset hut. I need to know how many cubic feet it can hold. Width=80 height = 24 length= 205 all in feet