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*** This is my interpretation of the problem:
dx/dt = a.sin( y(t) )
So, can't we express it in the first derivates of y(t) ? Thats what i'm looking for.
Forgive me if I am wrong, but it may simply be impossible without knowing the function y(t).
I'm not convinced... i dont get it really. Do you mead x = a(-cos(yt/y)) ?
∫dx = ∫ asinyt dt
Hi guys, I'm stuck again!