Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °
| |
|
|
You are not logged in. Post a replyTopic review (newest first)
Hi,
Luckily, this has been done already here
Show that there are no rational numbers 2x^2 - 3y^2 = 1 but that there are infinitely many rationals x, and y such that 2x^2 - 3y^2 = -1. |