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Another way to look at it is to think that a square root is also x^½ (x raised to the half power)
√a x √b= √(a x b), so 4√x³y x 4√xy² = 4√(x³y x xy²)
One more thing, is this a typo error agian or correct answer?
Hi thx for the reply.
I tried working backwards by squaring the answer, and found that you actually want to find to square root of: