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X=Z=Y I thought. Elseways you keep the X rest, the Y rest and the Z rest, Xr,Yr and Zr
That will not work LQ, the problem is more complicated, simple example in 2D to show; Code:_____5____   __3__   _____1 4  __________ with your method, you would have 5/3 > 1. 4/1 > 4. 1×4 = 4. however, you can fit 6. Code:_________ __1__   __2__56 __3____ __4_____ and in 3D this becomes even more evident, let's say the box was 4×5×3, and subbox was 3×1×1, you method would say you can fit 15. but you can fit 20. with the second diagram above, where each of those 6 boxes are, you could fit the same pattern ontop of it twice over, and then in the unused space you could put 2 more boxes in orientated vertically to make 20
First you divide the big box's X with the small box's X, the big box's Y with the small box's Y, the big box's Z with the small box's Z.
Hi, 