But how do you call increasing, decreasing... in one word? The ... of a function. In Dutch we call it "verloop", but it's the same like process..., but what's the right mathematical term?]]>

**Welcome to the forum!**

Sorry, thickhead, but I haven't looked at your method yet as I'm still struggling with my thoughts on this.

Anyway, I made another model that was much more accurate than before, and couldn't get it to agree with the straight-line method of my previous posts.

Using measurements from post #6 (pipe D=29, tape W=18 ), my model was giving an approx tape angle of 79°, so I had to rethink (sorry, Bob!)

I hit on an idea that I think(!) will work, and have this formula for it:

*Edit: Hmmm...looking at thickhead's solution, I think I have a small error. Getting there, though... *

Ah, yes...this should be it:

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Welcome to the forum.

I made a truth table (as you had this as your title ... wouldn't have otherwise) and got the following possibilities:

A & B did it.

A did it alone.

B & C did it.

C did it alone.

Thus I cannot determine an answer with these constraints.

Bob

]]>Welcome to the forum.

Force is measured in Newtons. Pressure is force/area.

Bob

]]>For the equation.

We use the solutions of the equation Pell.

Then the solution can write.

And again.

All the numbers can have any sign.

]]>Welcome to the forum.

If you have a version of Windows, you can use the software Paint.

I selected 'rose' from the colour chart and then 'edit colours' and got this:

Those 3 numbers down the right hand side are the colour components in decimal.

So you need to use the edit to find the exact colour you want, then write down the 3 numbers, convert to hex, and construct a 6 digit hex like this RRGGBB.

That should work.

Bob

]]>Welcome to the forum.

I've used 1 to stand for TRUE and 0 stands for FALSE.

Here's a part of the Karnaugh map:

The outcome will be true if A' AND C' is TRUE. So this will be when A AND C are both 0. So I entered 1s for these cases.

You need to do the same for the other components C'D' etc. Only put in 1s for each component.

When you're done, everything else must be a 0 in the outcome. The map is complete. Then it's just a matter of looking at the outcome column, trying to find a simple function that achieves those 1s and 0s.

I haven't made the full map myself yet so I don't know how easy that last step will be. If you're stuck, post your map and I'll have a look.

Bob

]]>Welcome to the forum.

I used 1 to stand for 'votes for' and zero for votes against. For the outcome, 1 stands for proposition passed and 0 for proposition rejected.

Here's a bit of the truth table:

When you complete it, you'll see that the first 4 outcomes conform to a simple function and so do the last 4, so an overall function should be possible.

Bob

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