Anyway, log[sub]*x*[/sub] where *x* < 1 problematic. If *x* < 1, then you actually have log[sub]*x*[/sub]*y* > 0 when *y* < 1 and log[sub]*x*[/sub]*y* < 0 when *y* > 1. With this in mind, I think youll find that not only

is invalid but also

is a solution set as well.

]]>6/10 is a solution and is in my solution set, so there's no contradiction.

If you're hinting at a more elegant method of reaching the answer, I'm afraid I don't get that either.

]]>let x=6/10]]>