Anyway, log[sub]x[/sub] where x < 1 problematic. If x < 1, then you actually have log[sub]x[/sub]y > 0 when y < 1 and log[sub]x[/sub]y < 0 when y > 1. With this in mind, I think youll find that not only
is invalid but also
is a solution set as well.
]]>If you're hinting at a more elegant method of reaching the answer, I'm afraid I don't get that either.
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