Welcome to the forum. That site looks like it might be useful for Russian speakers.

]]>Division of comlex polynomials

http://www.abakbot.ru/online-16/438-dpolynom

Morning to you! It would be a funny looking sweater!

Hi JFF;

My Jana, wunderbar! A clever idea and you correctly guessed that the school problem did not have a remainder.

But if it had been like the above problem that method of equating the coefficients gets a little bit nasty. This is due to the fact that your idea will tend to balance the remainder in b and c. This may not be desirable.

]]>It's almost like starting a new thread I suppose. Math is Fun has enough threads to weave a sweater!

Have a fantastic day!

]]>You can answer posts that are old if you feel you have something new to add.

]]>Boy how dumb of me. I didn't know we had threads for 5 year olds! He's way too young to be

doing this kinda stuff unless he's some kind of child progeny! Anyway when the threads get so

old we probably ought to buy a new wardrobe.

Surely he has gotten it by now!. I haven't paid much attention to the dates on the posts. Guess this

is a wake up call. Thanks for pointing it out.

Hang in there! You'll get it.

I hope he gets it by now. This is a 5 year old thread.

]]>From your post #6 it looks like you are trying to do something like

12 12 12 12

______ = __ + __ + __ which is not legitimate. Left side = 12/9 and right side = 4+3+6=13.

3+4+2 3 4 2

In the division algorithm the only term that we estimate (divide by) with is the first term. In your

division case it is the x squared. The x and the 2 are never used in estimations. It might help if

you review some of the arithmetic division problems like 5785/523 in which only the 5 is the

estimator at each step. The 2 and 3 are used in the multiplication steps but not in the estimations.

Perhaps you are confusing the above fraction with

3+4+2 3 4 2

______ = __ + __ + __ which is OK to do. It doesn't work with the fraction "flipped over."

12 12 12 12

Hang in there! You'll get it.

]]>That's a very interesting approach. I'll remember that.

And Xerxes, polynomial division works pretty much like division in arithmetic. Let's see if I can get

the numbers to line up fairly nicely in a post. I'll just use the coefficients.

The 1 of the divisor 1 1 2 is the estimator for the process.

3 2 -1 Estimate 1 into 3 to get the 3

_____________

1 1 2 | 3 5 7 3 -2

3 3 6 multiply the 3 times 1 1 2 to get this line

______

2 1 3 Subtract the 3 3 6 from the 3 5 7 to get 2 1 and bring down the 3

2 2 4 Estimate 1 into 2 and multiply 1 1 2 by 2 to get 2 2 4

______

-1 -1 -2 Subtract 2 2 4 from 2 1 3 to get - 1 -1 and bring down the -2

-1 -1 -2 Estimate 1 into -1 and multiply 1 1 2 by -1 to get -1 -1 -2

________

0 Subtract to get the remainder of zero.

If the remainder line had been something like 2 -3 then this would be 2x-3 in long form.

The basic algorithm is "estimate (division), then multiply, the subtract just like in arithmetic,

except now we are dealing with signed numbers. If you get double digit numbers in the process

you cannot carry between columns line in arithmetic.

This is a "repeated subtraction" algorithm and can be done in a short (place value) form since

the polynomials are place value in an unknown base x. But the process is basically the same

as that done in arithmetic except for now dealing with signed numbers.

And by the way, if you do get an estimation like 3 into 2 in a polynomial division then the number

to write up top is the fraction 2/3. This makes the following arithmetic quite messy most of the

time, but we have no choice since we can't "borrow" in unknown base arithmetic.

Most authors of algebra books avoid these nasty problems like the plague. They are quite happy

for the most part to "rig" the problems to be nice. It makes no difference to a program like

Maple whether the numbers "turn out nice" or not. It just crunches it out. But to us humans it

makes a big difference.

then expanded the right-hand side and compared coefficients.

]]>This one doesn't look like it would work out evenly, but the answer says otherwise.

]]>Can anyone show me the work for the second number in the answer?

]]>