Well then, sorry, RickIsAnIdiot, no offense meant then.
I probably should have written that up in LaTeX, I'll try sometime.
RickyIsAnIdiot
No Problem! so do you now agree your counter Math example is Flawed!...
As I stated... There is NO LIMIT OF .99999... AS 1
]]>Ack, another ARB sock puppet.
(At least, I think so...)
Moderation has been discussing this and our (hmm, perhaps my) best guess is no, it is not.
To be fair, RickIsAnIdiot has a point. To say "0.999..." has a limit is wrong. The increasing sequence of adding 9's:
0.9, 0.99, 0.999, 0.9999, ...
This sequence has a limit. And of course, this is what you meant (as context in your post shows).
And I have no idea what you were trying to do here:
limit as x goes to infinity (1-x(.1+.01+.001+.0001...))=0
limit as x goes to infinity (x(.1+.01+.001+.0001...))=1
The limit as x goes to infinity of 1 - x * 0.111... = 0?
]]>Also:
1-.9=.1
1-.99=.01
1-.999=.001
limit as x goes to infinity (1-x(.1+.01+.001+.0001...))=0
limit as x goes to infinity (x(.1+.01+.001+.0001...))=1
SO THE LIMIT OF .99999... IS 1
Q.E.D.
I think I know where Anthony is coming from. Infinity is kind of a hard concept for everyone (well... me for sure. It sure took me a while for me to figure it out).
RickIsAnIdiot
There is NO LIMIT OF .99999... AS 1 ( To Limit .9999... is to Stop the .9's being continuous!...as soon as you make a Limit it will be
contradictory!
Is there a flaw? I think so...:/
I don't think there is a flaw. I use this to prove that .999... = 1
]]>The Masses! cant Resist!...Fame is Good for the Soul!.................................................................................................................
]]>A.R.B
More like Silencing the MUCK!...
]]>Quote:" In case you! hadn't noticed! I was pointing! out an obvious! contradiction! of yourself! For instance! have! you heard of the! word! 'trolling'! "
A.R.B
In case you! hadn't noticed! Now try Some Math!...
Look, he's mocking your mock Devante
]]>