.... Or nothing. Proven.

]]>Typically, 0^0 is left undefined.

The exponential series equates it to one, which I believe is the limit, rather than zero.

Neither here nor there really

As for bases, think of numbers simply as symbols. So we start out defining "1" as the symbol for the first number (integer). Then we define the symbol "2" to stand for 1 + 1. And "3" simply means "2 + 1", or rather, "1 + 1 + 1". And so on.

So it makes no difference whether you use 0101 to represent 5 in binary, or 387 to represent 322 in base 9. They are just symbols and nothing more.

We most likely use base 10 because of the 10 digits (fingers) we have. But other cultures have used things such as base 60 in the past.

Why do computer scientists always get Halloween and Christmas mixed up?

'Cause 31 (Oct) = 25 (Dec)

]]>(Look for "Why not try it yourself?", and then make the thing count for you in base-2 then base-3 etc up to base-10)

]]>but you have totally confused me with the 0^0 thing!

Thats given me something to think about!

Thanks.

]]>0^3 = 0

0^2 = 0

0^1 = 0

0^0 = 1?

And to add even more confusion in there, as well as arguing whether it's 0 or 1, some people say that it's neither. But then those people argue about whether it's undefined or indeterminate.

]]>as you go down the series, you divide by n, n/n = 1

as you go up the series, you multiply by n, 1/n*n = 1

example there, as you go down, you divide by 2, 8->4->2->1->0.5->0.25

same going up, the only number that makes sense is 1.

the only time it doesnt really apply is in 0^0, but to keep it consistent, we say that 0^0 = 1 aswell, although often, youll just see it as undefined aswell.

]]>I can understand it algebraically:

x^m ÷ x^m = 1

x^m ÷ x^m = x^m-m = x°

∴ x° = 1

But I cannot understand how any number multiplied by itself 0 times would give 1? It doesn't make much sense logically to me. Can anyone explain how this works (bearing in mind i am 15 - so not too complicated please)?

Thank you.

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