For radians, if I don't divide by ten like the other ones.

Then the vertical distance is pi over 2 and horizontal distance is ONE!!!!

Cool huh!!!l Neato wild, huh???

All these curves are simply close-ups or enlargements of the other ones if you switch between

radians, degrees, and gradians.

Does anyone have any questions about this puzzle??]]>

Check it out for yourself before I give it away...

(smurk)]]>

This is the radius at .00001 degrees from horizontal. If I did it right.

For gradians, the curve is enlarged by 10/9, so it hits 6.366197723 or so and (0,10) on the vertical.

I guess that makes sense.]]>

This is how it works.

Use degrees, radians, gradians, it shouldn't matter, though I used degrees when I made the diagram.

For the 90 degree angle, straight upward, I drew a line from the center up 9 units in the CAD program.

For the 80 degree angle, I drew a line that extended at 80 degrees from horizontal, but stopped when the end of the line was at the height of 8 units above the horizontal axis.

I continued in this simple fashion.

So for 45 degree angle, the line segment ends where it is 4.5 units above the horizontal.

Pretty cool function, don't you think.

I think I worked it out into polar coordinates, and it had a cosecant in it, but I don't have my notebook out right now... Bye...]]>

That's what I called it because I am comparing (versus) mathysperson's

first guess to my curve.

I think the filename should give away the biggest clue to how I made the curve.

Good Luck with the puzzle...

That might help...

]]>And the picture is now not upsidedown for fun like original one.

The bold line is my original MYSTERY CURVE.

The new shell shaped curve with radial lines is the first guess with line lengths of 1 + sin(theta from horizontal).

Should be same as cosine of the phrase "90 minus theta".

Here's the plot below.]]>

If it is equivalent, this would surprise me.

I'll work out the lengths of the lines and see if it is close to 1 + cos of theta and get back to you.

My unreveiled method uses some other lengths, but not the length of the lines.]]>

Can anyone recognize the curve as anything??

I made it and I don't know the answer yet myself.

Is this curve a well-known curve??

Can you guess how I made it???

With what criteria??]]>