actualy the value of x^x^x^x^...:

Let s=x^x^x^...

s=x^(x^x^x^...)

s=x^s

So once we can sole this equation in terms of x then we get the value of s.

Which is approximately

1.111782011041844...

Welcome to the forum!

]]>Then further investigation revealed that there was a similar number to that, but it ended in 5.

8212890625 was the last bit. And there was the very peculiar property that if you added together the last n digits of both numbers, you always got 1000...0001, with (n-1) zeroes.

]]>(a) This is the maximum value of xth root of x for any value of x.

(b) This number is also the maximum value such that

x^x^x^x^x...............ad infinitum is finite.

The number is eth root of e, the Natural logarithm base.

e is approximately 2.7182818284.

2. 1787109376

It is known that the square or any higher power of a number ending in 6 is always 6.

This holds good for 76, 376, 9376, etc.

The ten digit number given also has this property.

This can be continued indefinitely, and you get more and more digits.

PS:- Try searching with Google for these numbers. You'd be surprised by the result

]]>