where does the 'e' dissapear off to?
]]>2) Now, note that T=70-c and our K above, use your third equation:
Move over 70, and use that (110-T)/c = (c+40)/c (which you can get from 110=T+c+40 in equation 2)
But e^ln(a)=a, so
Which gives c=-320.
3) So T=70-c=70+320=390.
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