mr.mathisfun ... i think u have got alot of these topics ... i really like them

can i see more ?]]>

Though I read it too.

Mathsisfun is good at fun maths and perhaps he is the best person you can consult to.

]]>For this problem, let 0 ≤ θ ≤ 2π. Now ask yourself, for what value of θ will *e[sup]i*θ[/sup] = *i*? Why yes, it's π/2!

So now we know that *e[sup]i*π/2[/sup] = *i*. Now let's take it to the next level:

Now if we remove the restriction 0 ≤ θ ≤ 2π, then we get the general solution

where *n* ∈ **Z**. I'm not sure why you have just *n* and not 2*n*, Ricky. Odd values of *n* in your solution would give

Now take a simple case of some 0 ≤ θ ≤ 2π that could give *e[sup]i*θ[/sup] = -i. 3π/2 is our value. Then

So, given the same interval 0 ≤ θ ≤ 2π, (-*i)[sup]i[/sup] ≠ i[sup]i[/sup]*, so I will conclude that your *n* should be 2*n*.

Interesting question though, I have to say.

]]>And then choose from Maths Puzzles and quizzes

And then onto Math and Logic Puzzles

]]>replies : 0

...

]]>as you all know i am an arabian person ... i decided to make a topic in an arabic forum about math '' enjoy the math '' and i need some questions , tricks , math magic ... to put there so i need your help lovely members !!! who can give me links ? who can put questions not difficult ones but cool and nice question which make you interested in math !!!

thanks again

]]>