a.) .03*.03*.03= .000027=.0027% chance

b.) .97*.97*.97= .912673= 91.26% chance

"A certain prescription drug produces side effects in 3% of the patients. Three patients that have taken this drug are selected at random. Find the probability that

a.) All three had side effects

b.) None of the three had side effects."

I am not even sure where to begin on this one so any help would be greatly appreciated. Thanks

Randy