have veneral disease (1/120)

and not have veneral disease (119/120)

from the first branch, you will two more branches

die from it (prob 1/12) end of branch = 1/1440

not die fro it (prob 11/12) end of branch = 11/1440

from the second branch, well, you dont really need any more branches, so just 119/120, since obviously, youre not going to die from a veneral disease, if you dont have it

and to check, adding it all together

1/1440 + 11/1440 + 119/120 = 1

]]>1B) We already know the chance of having it is 1/120, so having it AND dying from it is: (1/120)×(1/12) = (1/1440) = 0.0007 approximately.

]]>Q1) A servey of 3million people in britain found that 25000 of them had a venereal disease.

a) what is the probability of a person in britain having venereal disease.?

The survey also showe that once a person has a veneral disease, there is a 1 in 12 chance thats they will die from it within ten years.

fill in these probabilities, and any others that can bededuced on a tree diagram.CAREFULLY EXPLAIN the meanings of the probabilities at the ends of the branches.

b)what is the probability of a person having a venereal disease and dying from it within the next ten years.?

thanks in advance

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