a, b and c can only equal 9, 2 and -5 respectively, anything else wouldn't solve the equation. This is if a, b and c is not a function of x, of course, and just numbers.

]]>(3x-b)^2 - 9 = ax^2-12x+c

find a,b and c for all values of x

i was told taht

9x^2 -6xb+b^2 - 9=ax^2-12x + c

therefore, a must equal 9 b must equal minus 2

this emans that the equation falls nicely into place

then when x=0

b^2 - 9=c

substituting that in

-5=c

however, i argued that there was more than one solution and actually, becuase there is 4 variables, and only 1 equation, it is impossible to figure all the equation out with numbers

e.g c could equal anything, and this would balance out any differences, meaning that a,b or c could be anything

why am i wrong?

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