You're told that the line is parallel to 2x - 5y = 6. This means that your line will have the same gradient as that line.

Rearranging to y = mx+b form gives y = 2/5x - 6/5, so the gradient of your line is 2/5.

You are also told that your line passes through (-2,-3).

Using this combined with the gradient, you can find the y-intercept.

From the y-axis, the point has been moved left by 2, so you need to move it right 2 to get back there. You know that for every 1 that the point moves right, it goes 2/5 up, so you can work out that the y-intercept is -3+(2*2/5) = -2 1/5, or -11/5.

Therefore, your line is **5y = 2x - 11**.

# 3a

You find slopes by dividing the y-difference by the x-difference.

For PQ, that means (2-(-1)÷(4-1) = 3÷3 = 1

Similarly, for PR, the slope is (4-(-1)÷(6-1) = 5÷5 = 1.

# 3b

As the two slopes are the same, this means that all 3 points lie in a straight line.

We could have also concluded this by looking at question 3c. =P

# 3c

We already know that the slope is 1, which means that x and y will always have the same difference. We can see that this is -2.

Therefore, **y = x - 2**

# 3d

Using John's method, we can substitute the values in to see whether the equation is true or not.

This gives 8 = 10-2.

The equation is true, and so the point lies on the line.

]]>Simply put m and b into the y=mx+b equation, but leave the y and x as variables y and x, and this is your equation for the line!

So ANSWER is: y = (2/3)x + 1 + (2/3), which is the same as y = 2x/3 + 5/3, and also same as y = (1/3)(2x + 5).

Hope this helps a little bit.

Also, you might have been taught a different way, so sorry if this isn't how you should do it.]]>

Okay, so 1 for y = (2/3) times (-1) for x plus b.

Or y = mx + b, so 1 = (2/3)(-1) + b.

Multiply the -1 and add to other side.

1 + (2/3) = b

Now you know b! Horray!!! And you know m! Ever noticed people avoid the ! mark because it means factorial in math?

Now you know the slant of the line is up and to the right because m positive. It slants sort of at 2 o'clock. This is a rough guess, but the actual number for m is two-thirds. m = (2/3)

Now you can plug this number m and an x,y point into the y = mx + b equation and solve for b.

Then when you know b's value, then the equation will be y=#x + #, where # is two different numbers.

The y and the x stay in the final answer.

Okay, substituting we get, well I would tell you except I can't see the problem when I am typing.

Hold on, I have to go out of this...

Oh yeah, one of the points is (-1,1), so let x = -1 when y = 1, and m = (2/3), and try to find b.

In case you didn't follow that, you take the last numbers in the coordinates and subtract them and make that the top of the fraction for the m number, and you take the first numbers of the coordinates and subtract them for the bottom of the fraction.

This fraction is the m number, which is the slope of the line, or the tangent of the angle with the horizontal.]]>

1.

Write the equation of a line that passes through the indicated points: O(2,3) and P(-1,1)

2.

Find the equation of a line that passes through (-2,-3) and parallel to the line whose equation is 2x - 5y = 6.

3.

Given the points P(1,-1), Q(4,2), and R(6,4),

a. Find the slopes of line segments PQ and PR.

b. From your answer to part a, what can you conclude regarding the points P, Q, and R?

c. Find the equation of the line that passes through P and R.

d. Does the point S(10,8) lie on the line PR? Why or why not?

(The underlined letters are supposed to be lined on top.)

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