This is kind of complicated, but I'm getting what you're saying. How did you learn all this? Are you a maths genius?

Oh, and I was kind of worried that there was no answer since I have to hand in this assignment tomorrow.

Anyway, thanks for replying. It helped a lot.

]]>Now we have the normals. I'm going to assume we want outward facing normals, although I'm not entirely sure why that fact isn't given to you.

Finally, let:

So now:

Then we have:

Not quite sure why latex doesn't format that right, but at least it's readable.

After integrating all of these, I get 760. Is that what you get doing the divergence thm?

]]>George, I tried your method, it seems like whether z=0 or z=5, it doesn't affect the equation at all because when I take the partials of x and y, the z part disappears.

]]>z=5, 0<x<2, 0<y<4

......]]>

a) between the x and y (limits 2,0 and 4,0)

b) between x and z (limits 2,0 and 5,0)

c) between y and z (limits 4,0 and 5,0)

What are the other 3 integrals I need to set up?

]]>Ugly, but I think it will work.

]]>Thanks for the prompt reply of my other question today. Here's another one.

The problem with this one is that, the surface integral formula only has 2 variables in it, x and y. But this one has another z variable (the k term).

So how do I go about doing this? (I did grad . F already before this)

And no, I can't use the divergence theorem here because I'm supposed to prove it.

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