<![CDATA[Math Is Fun Forum / yet another problem]]>2005-04-20T18:49:29ZFluxBBhttp://www.mathisfunforum.com/viewtopic.php?id=335<![CDATA[Re: yet another problem]]>Total excavated earth: Pi*5.5m squared*7km=665500 cubic metres (Taking Pi as 22/7) Length of road covered: 665500/(0.5m*11m)=121km.

Answer: 121km

]]>2005-04-20T18:49:29Zhttp://www.mathisfunforum.com/viewtopic.php?pid=3108#p3108<![CDATA[Re: yet another problem]]>thanks for that quotation and more espcially for the help]]>http://www.mathisfunforum.com/profile.php?id=962005-04-15T13:29:39Zhttp://www.mathisfunforum.com/viewtopic.php?pid=2434#p2434<![CDATA[Re: yet another problem]]>These are nice problems ...

I think this one can be solved by just working out the volumes. Figure the volume of the cylinder, then divide it by (0.5 x 11).

]]>http://www.mathisfunforum.com/profile.php?id=22005-04-04T21:50:39Zhttp://www.mathisfunforum.com/viewtopic.php?pid=1293#p1293<![CDATA[yet another problem]]>A cylindrical tunnel 5.5m in diameter is driven through a mountain for a distance of 7km. the ezcavated earth i s spread to a depth of 50cm on the surface of a road 11m wide. Calculate the number of ilometers of the road that can be covered with all of the excavated earth. (Take pi as 22/7)]]>http://www.mathisfunforum.com/profile.php?id=962005-04-04T15:35:06Zhttp://www.mathisfunforum.com/viewtopic.php?pid=1286#p1286