so the column has a radius of three meters.

(3 + spike)cos 40°=3, ∴ spike height = 0.91622 meters.

tan 40°=(3sin50°+6)/((dist_from_column)+(3-3cos50°)), ∴ boy to column is 8.81769 meters.

For a double check, tan40°=rise over run=(7.5-1.5+3+spike_height)/(boy_to_column + column_radius_of_3).

]]>Yes, it needs triangles to solve. And the spike's height can likewise be solved.

Could you crunch the numbers, and see if you agree with my 8.24m distance to centre line of dome?

Oh, and if you can spare the time you are most welcome to drop by the forum every so often and help with some of the "Help Me!" problems.

]]>I could be wrong.

I read the question as the boy's line of sight doesn't touch the top of the dome - it passes somewhere else. That is we are considering a triangle with angle of elevation 40 degrees, meeting a circle at a tangent (probably not at the top).

Thus I would reduce the problem problem to one using similar triangles, by pythagoras, then use a triangle starting at a height 7.5m where the top angle of the triangle is 90 degrees (tangent to a circle).

Finding the height of the spike is merely similar triangles.

Finding the distance from the tower will involve finding the centre of the tower.

]]>This makes a triangle ABC with A being the eye, B being the base of the circle and C being the center of the circle. We know the circle has an angle at A of 20°, and line BC is 3m (half of the 6m diameter).

Solving this triangle: tan 20° = 3m / line length (AB), so AB = 3m / tan 20° = 8.24 m

The question asks "the distance the boy is from the nearest point of the tower.", well we have just figured out that the boy is 8.24m from the centre line of the tower, the tower is 6m in diameter, so he is 8.24 - 3 = 5.24m away from the outer wall

Now all that is left is that spike !

]]>This is how I would start:

Forget all the 3 dimensional stuff, it is really a 2d puzzle, so just write it down on a sheet of paper:

| (spike)

.-' (circle 6m diameter)

.-' ^

eye------------ 7.5m

1.5m

---+-----------------------------------

Draw a circle 6m in diameter with its centre 7.5m up. Draw a line (eye height) 1.5m up. Now draw a line at 40° that just grazes the circle.

You could now measure off the paper how far away the boy is standing (by where the 40° and the "eye-line" intersect), and the length of the spike (the distance from the top of the circle upwards to the 40° line), but we should really do all the math!

The puzzler has made it easy for us, I think, by having the circle's diameter 6m, which is exactly the same as the difference in heights (7.5m-1.5m=6m), or else it is just coincidence

]]>Please I really need this help]]>