g-1(f-1)(1)
Do you mean "g inverse composed with f inverse of 1"? Or mathimatically, g-¹(f-¹(1))?
If so, f-¹(1) = 5, and g-¹(5) = 2, so g-¹(f-¹(1)) = 2.
2.
f(x) = 2x - 2, f(x + h) = 2(x + h) - 2
f(x + h) - f(x) = 2x + 2h - 2 - (2x - 2) = 2h.
Now, I believe what you are trying to find is:
(f(x+h) - f(x)) / h
in which case its: 2h / h = 2.
]]>answers a.1, b.2, c.3, d.4, e.5
2nd problem
if f(x)=2x2 then f(xth)-f(x)=
4x-1 (x+h)-x
answers a. 4x+4
2h
b. 2h2-4x+1
h
c. 4xh+2h2+8x-2
d. 2x+4
e. 2
]]>