14 people (humans) = 28 eyes
2 martians = 6 eyes
Everyone had 2 eyes at least so that would be 14*2=28 take 28 from 34 and you know that you need 6 martains to equal 34 eyes!? or
]]>Here's the way I did it, a very non-matimatical way.
Let's assume that everyone is human. Then there are 28 eyes. For every human we replace with a martian, the net gain is 1 eye.
We need to gain 34-28 = 6 eyes, meaning there are 6 martians. Thus, there are 8 humans.
That's not very non-mathematical. It's logical at least, and logic fits in very micely with maths.
It's just a bit unconventional. It's how I'd have done it, though.
This is how I teach my students to approach problems involving Simultaneous equations. Most examinations give about half a minute or less to solve such problems, and I think this is the best way it can be done!
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But I also had a feeling kkkkk didn't know how to solve systems of equations yet. But I see no other mathimatical way to do it.
]]>3x + 2y = 34 (3 eyes for each martian, 2 for each human, is equal to 34)
x + y = 14 (martians and humans combine to 14 people total)
we need to solve for y, ill choose the second equation and get:
y=-x + 14
Now substitue that in for y in the first equation and simplify:
3x + 2(-x + 14) = 34
3x - 2x + 28 = 34
x = 6
Now since X stands for martians, we know we have 6 martians, leaving us with 8 humans.
If you plug those in for the first equation you will find 3(6) + 2(8) = 34, thus there are:
6 Martians (18 eyes) and 8 (16 eyes) Humans.
]]>Let's assume that everyone is human. Then there are 28 eyes. For every human we replace with a martian, the net gain is 1 eye.
We need to gain 34-28 = 6 eyes, meaning there are 6 martians. Thus, there are 8 humans.
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