14 people (humans) = 28 eyes

2 martians = 6 eyes

Everyone had 2 eyes at least so that would be 14*2=28 take 28 from 34 and you know that you need 6 martains to equal 34 eyes!? or

]]>Here's the way I did it, a very non-matimatical way.

Let's assume that everyone is human. Then there are 28 eyes. For every human we replace with a martian, the net gain is 1 eye.

We need to gain 34-28 = 6 eyes, meaning there are 6 martians. Thus, there are 8 humans.

That's not very non-mathematical. It's logical at least, and logic fits in very micely with maths.

It's just a bit unconventional. It's how I'd have done it, though.

m+e=14--->2m+2e=28

Therefore, m=6, e=8.

No. of maritans=6, no. of earthlings=8.

(Time taken = about 15 seconds)

This is how I teach my students to approach problems involving Simultaneous equations. Most examinations give about half a minute or less to solve such problems, and I think this is the best way it can be done!

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But I also had a feeling kkkkk didn't know how to solve systems of equations yet. But I see no other mathimatical way to do it.

]]>3x + 2y = 34 (3 eyes for each martian, 2 for each human, is equal to 34)

x + y = 14 (martians and humans combine to 14 people total)

we need to solve for y, ill choose the second equation and get:

y=-x + 14

Now substitue that in for y in the first equation and simplify:

3x + 2(-x + 14) = 34

3x - 2x + 28 = 34

x = 6

Now since X stands for martians, we know we have 6 martians, leaving us with 8 humans.

If you plug those in for the first equation you will find 3(6) + 2(8) = 34, thus there are:

6 Martians (18 eyes) and 8 (16 eyes) Humans.

]]>Let's assume that everyone is human. Then there are 28 eyes. For every human we replace with a martian, the net gain is 1 eye.

We need to gain 34-28 = 6 eyes, meaning there are 6 martians. Thus, there are 8 humans.

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