Just like there are 10³ possible decimal numbers between 000 and 999

]]>For now, i have to ways in mind...it's either

5 x 5 x 5

OR

1st condition- all numbers are different = 5p3

2nd condition- 2 num r de same, 1 is diff = (3p3/2p2) x 4

3rd condition- all num r de same = (3p3/3p3)

and add all the answers together..

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i'm nt sure which would b a better way..or the correct way..pls help..

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