ad+bc=-5]]>

cd=7

a+b=-1

ab+d+c=-10]]>

But it isn't krisper. Factoring a quartic equation is only an exercise if you are bored or insane. No math teacher woudl ever have you do this, nor would you learn anything from doing it.

]]>Can you show us the algorithm that is being used or write here how x^4 - x^3 - 10x^2 - 5x + 7 = 0 is being factored as it is very important for me to understand it. Thanks.

]]>Nah, I used a ti-89. It uses some fairly complex algorithms to do it, most of which would be unusable by a human.

]]>Was it trial and error, or was there some obscure method that I haven't heard of?]]>

x^4 - x^3 - 10x^2 - 5x + 7 = 0

Which factors into:

(x^2 + x - 1)(x^2 - 2x - 7) = 0

And you use the quadratic from there. It comes out to (-√5 + 1)/2, (√5- 1)/2, -2√2 + 1, and 2√2 - 1.

]]>I have a problem with an equation. Here it is: (x^2 + 4x + 5)/(x+1) = 3√(x+2). I have tried everything but still not getting the roots?! Please help. Thanks.]]>