No, sorry...they both dip out.
The first one was born 1 day too late and the second 1 day too early to meet the 'number of days into the year' constraint.
But them's the breaks!
I drew this up in Excel for a 199-year period, and there is a definite pattern that would be broken if we let these two would-be gatecrashers in!
]]>It'll never happen to me, though.
...so now you know when my birthday isn't.
]]>Sorry...made a huge blunder with the wording! Left an important bit out!
This is a puzzle given to me years ago by someone whose birthday fitted, and I'd forgotten about it until now.
Of course, I've lost the puzzle and repeated it from memory (which is never the best way for me), and only just now did I realise that there was a bit missing.
Fixed now, and should be a little more interesting.
]]>Thanks for your answer - and excellent thought - but single-digit ages are not exactly what I had in mind. Maybe my wording's a bit loose.
It's probably ok mathematically on occasion, but not really when applied to ages. That's here, down under, in Australia, anyway...but maybe we're a little different from the rest of you.
When their great day arrives, a 07-year-old kid is hardly likely to say to their classmates, "Hey! Guess what! I'm zero-eight today!!" Then they'll have zero-one heck of a job trying to explain to the other single-digit-year-olds in their class what on earth they meant by that! It'd probably take the kid until well after their 05-past-03 home time before any-zero-one would get it!
Please forgive me!
]]>What is the next birthday date on which some people will turn the age that is the last two digits of their year of birth, and that:
(a) has the same day and month as their birthday; and
(b) is the same number of days into the year as their number of birthdays. eg, someone celebrating their 43rd birthday must have their birthday on the 12th of February (ie, 31 Jan days + 12 Feb days = 43).