Nah we just pretend to be.

lol...of course you all are....I am the stupid one..hehehe

]]>katy.]]>

If you forget what the descriminant is:

You can find the roots of a quadratic equation of the form:

ax^2 + bx + c

using the quadratic formula:

(-b +- √ b^2 - 4ac)/2a

the part of the formula inside the radical side is the descriminant.

√ b^2 - 4ac

when the descriminant (b^2 - 4ac) is positive, it has two real roots. When it is negative, it will require the square root of a negative number and thus only has imaginary roots. When the discriminant is 0 the roots will be -b/2a + 0, and -b/2a - 0 which are obviously equal.

]]>The parabloa is quadratic surve. So you're right.]]>

I have one more question:

1)Explain when a parabola will have 2 real roots, 2 imaginary roots, and 2 equal real roots.Explain what characteristics the discriminant will have for the above cases

My answer is:

discriminant>0 (2 real roots)

discriminant<0(2 imaginary roots)

discriminant=0(2 equal real roots)

is it right?]]>

And something else :

10>3^2 => discriminant is > 0.

The discriminant is the bit inside the square root of the quadratic equation:

In this case, the discriminant would be 3² - 4*2*(-10) = 89.

Because it is positive, this shows that both roots will be real and distinct.]]>

Actually I don't know how to solve it without solving it.

X1/2= (+-sqr(89)-3)/4?]]>

y=34-x

Substitute in 1:

Let {is} means "must be"

x^2+(34-x)^2 {is} min =>

x^2+34^2-68x+x^2 {is} min =>

2x^2-68x {is} min =>

2(x^2 - 34x) {is} min =>

x^2 - 34x {is} min =>

x^2 - 2.17.x {is} min =>

(here is the thin moment...)

x^2-2.17x+17^2 {is} min =>

(x-17)^2 {is} min =>

(x-17)^2=0

x=17

y=34-17=17]]>