I'm not sure what you mean by vertex, but I'll guess you mean the turning point. To find that, you need to complete the square.

Completing the square for this example would give 2(x + 1)² + 1. (x + 1)² is always positive, so it is smallest when it is equal to 0. This is when x = -1 and so that is your turning point.

]]>General formula :

ax^2 + bx + c = 0

First find Delta Δ = b^2 - 4ac

x1 = ( -b + √Δ ) / 2a

x2 = ( -b - √Δ ) / 2a

If b is even , you can take delta = b^2 - ac , if i remember correctly, and instead of 2a, u use a in the denominator.

Anyway the roots should be :

x1 = - 0.29

x2 = -1.7

Concerning the intercepts, just equate x and y to 0 for a general equation. In this case, this is a parabola, so the roots found are x intercept and the y intercept is 0.

]]>I need help finding the y and x intercepts and vertex!

I also need to use the quadratic formula to find, whatever that formula finds.... Please help!

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