Hi;

Did you understand what happened? I can do more examples if you need them.

Nah it's okay !

]]>Did you understand what happened? I can do more examples if you need them.

]]>According to the template we now just need to solve

we get

Now we have n1,n2 and n3 so

we have found the cube root of the RHS!

Ah ok! Well, thank you for taking your time.

]]>we get

Now we have n1,n2 and n3 so

we have found the cube root of the RHS!

]]>Not exactly, it is a -36.

yes

]]>3) Now take a look at the abc term. What do you see?

That we have 36 ???

]]>2) Look at the coefficient in front of c^3 in my example. It is -27. Take the cube root of it. So n3 = -3.

Following

]]>It is easier to use this:

1) Look at the coefficient in front of a^3 in my example. It is 8. Take the cube root of it. So n1 = 2. Follow so far?

yes

]]>1) Look at the coefficient in front of a^3 in my example. It is 8. Take the cube root of it. So n1 = 2. Follow so far?

]]>Can you extend that to a cubed form?

Well, I don't know. Let's hope that we can....

]]>We have :

a^2+2ab+b^2

Now we know that the first term of the root will be "a"

so...

a^2+2ab+b^2(a

"a" squared cancels the other a^2

2ab+b^2(a

Now, we know that 2ab+b^2=(2a+b)b and so if we can figure out a divisor, we will also know the root. We also know the first term of the divisor because it is always the double of the firm term of the root. (Look at the square root algorithm :http://www.basic-mathematics.com/square-root-algorithm.html)

2ab+b^2(a+b (we find, by luck I guess, that we have "b" for the second term.)

____________

2a+b)2ab+b^2

2ab+b^2

______________

0

Anyway, i was searching for something like what I described.

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