Based on that understanding, the type of animal in each stall is independent from the types in the other stalls, and there are exactly 3 ways to fill each stall, so the total number of loadings is 3*3*3*...*3 = 3^10.
]]>hmmm, this sentence confused me.
Confused me too.
]]>thanks.
]]>so it was all about this.
"animals of each kind being not less than 10" <---what was the use of this sentence then
I do not know but who cares?
]]>For Each stall , you can do it in 3 ways (i.e, one of cows or calves or horses)
For 10 stalls, you can do it in 3^10 Ways
]]>{cow, cow, calf, horse, cow, horse, horse, calf, calf, cow}
here is another
{horse, cow, calf, cow, cow, cow, cow, horse, calf, cow}
and another
{cow, cow, horse, calf, horse, calf, calf, cow, cow, calf}.
Do you see that each stall has 3 choices, a cow or a horse or a calf?
]]>Is that the exact wording of the problem?
]]>