By equation of the sphere its already given that the sphere is at origin (0,0,0).

Now from there we get radius of the sphere is

Now we have to find the distance 'd' of the plane from origin and that will be

Now use Pythagoras theorem to find the radius of the section by the plane

Good Luck

]]>You could treat the two equations as simultaneous and find the equation of their intersection. Buit this is hard work. So here's a quicker method.

http://www.enm.bris.ac.uk/admin/courses … ov2009.pdf

Section called Point and a Plane. 3.37

n is the normal to the plane ie n = (3,2,-1) and take a as a = (0,0,0)

d = 5root14

once you have p you can use pythag on the radius of the sphere as the hypotenuse and find r, the radius of the circle.

Bob

]]>Bob

]]>I get that too.

Bob

]]>My answer came out to

Did I did it correctly,I am bit confused over the question.

Thanks

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