you don't have use trig, the triangles are 30-60-90, so sides are 2:1:sqrt(3)
Hhhmmm. And where did that result come from, I wonder?
Bob
]]>Very good! Well done.
]]>]]>
Don't know if this is the quickest way but it should work.
Box in the hexagon as shown in my diagram. (All the angles are 120)
Use trig to calculate the length and width of the box.
Calculate its area and subtract the areas of the unwanted triangles.
Bob
]]>