We have no particular solution just a 1 general one. To continue with this route he will need 2 different general solutions.
]]>That is what I am saying. If there is only one solution. Is there another solution?
There should be..because v1 and v2 are linearly independent
]]>Of course you do, but you already got the solution to DE earlier.
But then don't we find that v1(x)=v2(x) ? Or not? I haven't understood...
]]>That is true but have you used the solutions to compute the wronskian?
Can't I just write that the Wronskian is equal to:
| v_{1}(0) (v_{1}(0))' |
| v_{2}(0) (v_{2}(0))' |
Do you mean that I have to solve the differential equation that is given for
and ?]]>How do you know the two solutions are linearly independent?
Because the exercise says that v1,v2 are solutions of the differential equation so that
is not constant..So,I do not know why it should be non zero.
Did you compute the Wronskian?
Because there is a theorem that says that if two solutions of a differential equation are linearly independent,their Wronskian is nonzero!!!
]]>Did you compute the Wronskian?
]]>Without getting the 2 constants v1 = v2, therefore the above expression will always be 0.
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