Bob
]]>Bob
]]>hi J
%4 is good for the triangle.
Shape EAFD is a rectangle. EA was given as 8. AF = AB + BF.
You got 9 for BF (although you wrote AF). So AF = 10 + 9.
Nearly there.
Bob
Hello Sir,
So the area of the rectangle EAFD would be 152(8x19)
Now I would add both areas together which would be:
152+54=206
So my final answer would be 206
%4 is good for the triangle.
Shape EAFD is a rectangle. EA was given as 8. AF = AB + BF.
You got 9 for BF (although you wrote AF). So AF = 10 + 9.
Nearly there.
Bob
]]>hi Peccatrix123
I understand EA, BC, CD, I'm just confused by where point F is. Is F where the shape kind of slants?
Also, would FC be 12?If you continue the line AB until it crosses CD, that is the point F.
The four points EAFD makes a rectangle. It looks like you have got this, because FC is 12, well done.
And BCF is a right-angled triangle.
So now use Pythagoras' theorem to calculate BF. You'll have all the measurements you need to calculate the two areas.
Bob
Hello sir,
Using pythag, I solved for AF which I got 9. Then I solved for the area of the triangle(0.5 x12x9) which I got 54. For the area of the rectangle EAFD, I'm confused. What is FD? I know EA is 8, but do I have to use pythag also to find FD?
Thanks,
J
hi Peccatrix123
I understand EA, BC, CD, I'm just confused by where point F is. Is F where the shape kind of slants?
Also, would FC be 12?If you continue the line AB until it crosses CD, that is the point F.
The four points EAFD make a rectangle. It looks like you have got this, because FC is 12, well done.
And BCF is a right angled triangle.
So now use Pythagoras' theorem to calculate BF. You'll have all the measurements you need to calculate the two areas.
Bob
Hello Bob. About how many questions belong to the Unanswered section? Does it make sense to answer unanswered questions posted prior to the current year?
Thanks.
P. S. I really think this forum would benefit more if it was divided by courses. This is simply my opinion. Take a look at freemathhelp.com or mathhelpboard.com and others like it.
]]>I understand EA, BC, CD, I'm just confused by where point F is. Is F where the shape kind of slants?
Also, would FC be 12?
If you continue the line AB until it crosses CD, that is the point F.
The four points EAFD make a rectangle. It looks like you have got this, because FC is 12, well done.
And BCF is a right angled triangle.
So now use Pythagoras' theorem to calculate BF. You'll have all the measurements you need to calculate the two areas.
Bob
]]>3 things,
1. This was from about 8 years ago
2. The question being asked right now is only asking for one of the questions not all.
3. I dont think the original poster is active anymore
Hope this helps
Thanks for clearing this up for me.
]]>1. This was from about 8 years ago
2. The question being asked right now is only asking for one of the questions not all.
3. I dont think the original poster is active anymore
Hope this helps
]]>Just need some help understanding some of these math problems and checking the ones I already did (if right/wrong). Thank you for your time:
1. An equilateral triangle with a side of 1 inch - Answer: A
A 0.43 sq in
B 0.56 sq in
C 0.89 sq in
D 0.23 sq in
E 0.19 sq in
F 0.54 sq in2. A square with a side of 2 feet - Answer: B
A 9 sq ft
B 4 sq ft
C 2 sq ft
D 7 sq ft
E 3 sq ft
F 8 sq ft3. A regular pentagon with a side of 3 centimeters - Answer: F
A 23.01 sq cm
B 12.34 sq cm
C 39.17 sq cm
D 9.46 sq cm
E 34.21 sq cm
F 15.48 sq cm4. A regular hexagon with a side of 10 cm - Answer: D
A 641.25 sq cm
B 194.45 sq cm
C 361.25 sq cm
D 259.81 sq cm
E 105.22 sq cm
F 453.01 sq cm5. A regular heptagon with a side of 7 inches. ***need help understanding how to solve***
A 178.06 sq in
B 294.16 sq in
C 169.21 sq in
D 358.91 sq in
E 157.36 sq in
F 277.91 sq in6. A trapezoid where the height is 18 cm, base 1 = 16 cm and b2 = 8 cm. - Answer: C
A 178.06 sq cm
B 122.5 sq cm
C 216 sq cm
D 230 sq cm
E 280.9 sq cm
F 510 sq cm7. A trapezoid where the height = 7 mm, base 1 = 26 mm and base 2 = 9 mm. - Answer: B
A 178.06 sq mm
B 122.5 sq mm
C 216 sq mm
D 230 sq mm
E 28.9 mm
F 510 mmFill in the missing information for the following trapezoids:
8.
height = 19.8 cm
b1 = ________
b2 = 14.4 cm
area = 401.94 cm2 - Answer: A
A 26.2 cm
B 12.5 cm
C 216 cm
D 23 cm
E 28.9 cm
F 51 cm9.
height = 23 mm
b1 = 23 mm
b2 = ________
area = 529 mm2 - Answer: D
A 78.06 sq mm
B 22.5 sq mm
C 21.6 mm
D 23 mm
E 28.9 mm
F 30 mm^210.
height = ________
b1 = 20 cm
b2 = 21 cm
area = 205 cm2 - Answer: D
A 17.06 cm
B 12.5 sq cm
C 26 cm
D 10 cm
E 28.9 cm
F 50 cm^211.
height = 28.9 m
b1 = 26.9 m
b2 = ________
area = 806.31 m^2 - Answer: EA 17.06 sq m
B 15 m
C 46 m
D 23 m
E 28.9 m
F 51 m12. If the area of a parallelogram is 690.84 m^2 and the height is 20.2 m, what is the length of the base? - Answer: D
A 78.06 m
B 22.5 m
C 216 m
D 34.2 m
E 28.9 m
F 51 m13. If the base of a rectangle is 28 cm and the area is 588 cm^2, what is the height of the rectangle? - Answer: E
A 17.06 cm
B 122.5 sq cm
C 216 sq cm
D 23 cm
E 21 cm
F 51 cm^214. If the height of a rectangle is 26.1 m and the base is 17.3 m, what is the area of the rectangle? - Answer: A
A 451.53 m^2
B 122.5 m^2
C 216 m^2
D 430 m^2
E 289 m^2
F 510 m^215. If the height of a parallelogram is 34 cm and the base is 15 cm, what is the area of the parallelogram? - Answer: F
A 178.06 cm^2
B 122.5 cm^2
C 216 cm^2
D 230 cm^2
E 289 cm^2
F 510 cm^216. What is the area of a parallelogram with height 26 cm, base 16 cm, and side length 28 cm?***need help understanding how to solve***
A 178.06 sq cm
B 122.5 sq cm
C 216 sq cm
D 416 cm^2
E 28.9 cm
F 510 cm^217. What is the area of a regular octagon with a side of 6 cm? ***need help understanding how to solve***
A 178.06 sq cm
B 122.5 sq cm
C 216 sq cm
D 23 cm^2
E 173.82 cm^2
F 510 cm^218. What is the area of this polygon?***need help understanding how to solve***
http://www.compuhigh.com/linkme/admin/testeditor/upload/pics/geometry/lesson21/area1.gifls_XF = 53 mm ls_XV = 72 mm ls_VR = 16 mm
ls_FB = 31 mm ls_BT = 31 mm ls_EU = 47 mm
ls_UL = 31 mm ls_TL = 88 mm ls_DE = 16 mm
ls_RM = 70 mm ls_MC = 21 mm ls_DC = 70 mmA 8014 mm2
B7030 mm2
C6027 mm2
D5478 mm2
E 1782 mm2
F 1225 mm219. What is the area of this rectangle?***need help understanding how to solve***
http://www.compuhigh.com/linkme/admin/testeditor/upload/pics/geometry/lesson21/area2.jpgA 17.06 sq units
B60 sq units
C21.6 sq units
D53 sq units
E 28.9 sq units
F 51 sq units20. What is the area of this polygon?***need help understanding how to solve***
http://www.compuhigh.com/linkme/admin/testeditor/upload/pics/geometry/lesson21/area3.jpgA 178 sq units
B129 sq units
C230 sq units
D240 sq units
E 219 sq units
F 206 sq units
1. Post no more than two problems at a time. Give tutors a chance to reply.
2. Show your effort, your math work. By doing so, it helps the tutors here to know where you stand, mathematically speaking.
3. I like your questions but please be specific in terms of directions. For example, don't say this: y = mx + b. Help. What? Help in what way? This is just an example.
4. Give tutors a chance to reply. Many tutors work full-time and NO ONE HERE is getting paid to help out with hundreds of daily questions. I myself use the site as a tutor and as a person learning mathematics.
5. What grade are you in? What math course are you taking?
]]>hi demha
I assume you are asked for the areas here.
1. An equilateral triangle with a side of 1 inch - Answer: A
A 0.43 sq in
B 0.56 sq in
C 0.89 sq in
D 0.23 sq in
E 0.19 sq in
F 0.54 sq inCorrect.
2. A square with a side of 2 feet - Answer: B
A 9 sq ft
B 4 sq ft
C 2 sq ft
D 7 sq ft
E 3 sq ft
F 8 sq ftCorrect.
3. A regular pentagon with a side of 3 centimeters - Answer: F
A 23.01 sq cm
B 12.34 sq cm
C 39.17 sq cm
D 9.46 sq cm
E 34.21 sq cm
F 15.48 sq cmCorrect.
4. A regular hexagon with a side of 10 cm - Answer: D
A 641.25 sq cm
B 194.45 sq cm
C 361.25 sq cm
D 259.81 sq cm
E 105.22 sq cm
F 453.01 sq cmCorrect.
5. A regular heptagon with a side of 7 inches. ***need help understanding how to solve***
A 178.06 sq in
B 294.16 sq in
C 169.21 sq in
D 358.91 sq in
E 157.36 sq in
F 277.91 sq inHow did you do the previous ones? I'm doing them like this: (i) 360/7 to get the central angle for one of 7 identical triangles. (ii) Split this angle in half to create a right angled triangle (iii) Use tan to get the height of the triangle (iv) half base x height for the area of one (v) x by 7 to get area of heptagon
6. A trapezoid where the height is 18 cm, base 1 = 16 cm and b2 = 8 cm. - Answer: C
A 178.06 sq cm
B 122.5 sq cm
C 216 sq cm
D 230 sq cm
E 280.9 sq cm
F 510 sq cmCorrect.
7. A trapezoid where the height = 7 mm, base 1 = 26 mm and base 2 = 9 mm. - Answer: B
A 178.06 sq mm
B 122.5 sq mm
C 216 sq mm
D 230 sq mm
E 28.9 mm
F 510 mmCorrect.
Fill in the missing information for the following trapezoids:
8.
height = 19.8 cm
b1 = ________
b2 = 14.4 cm
area = 401.94 cm2 - Answer: A
A 26.2 cm
B 12.5 cm
C 216 cm
D 23 cm
E 28.9 cm
F 51 cmCorrect.
9.
height = 23 mm
b1 = 23 mm
b2 = ________
area = 529 mm2 - Answer: D
A 78.06 sq mm
B 22.5 sq mm
C 21.6 mm
D 23 mm
E 28.9 mm
F 30 mm^2Correct.
10.
height = ________
b1 = 20 cm
b2 = 21 cm
area = 205 cm2 - Answer: D
A 17.06 cm
B 12.5 sq cm
C 26 cm
D 10 cm
E 28.9 cm
F 50 cm^2Correct.
11.
height = 28.9 m
b1 = 26.9 m
b2 = ________
area = 806.31 m^2 - Answer: EA 17.06 sq m
B 15 m
C 46 m
D 23 m
E 28.9 m
F 51 mCorrect.
12. If the area of a parallelogram is 690.84 m^2 and the height is 20.2 m, what is the length of the base? - Answer: D
A 78.06 m
B 22.5 m
C 216 m
D 34.2 m
E 28.9 m
F 51 mCorrect.
13. If the base of a rectangle is 28 cm and the area is 588 cm^2, what is the height of the rectangle? - Answer: E
A 17.06 cm
B 122.5 sq cm
C 216 sq cm
D 23 cm
E 21 cm
F 51 cm^2Correct.
14. If the height of a rectangle is 26.1 m and the base is 17.3 m, what is the area of the rectangle? - Answer: A
A 451.53 m^2
B 122.5 m^2
C 216 m^2
D 430 m^2
E 289 m^2
F 510 m^2Correct.
15. If the height of a parallelogram is 34 cm and the base is 15 cm, what is the area of the parallelogram? - Answer: F
A 178.06 cm^2
B 122.5 cm^2
C 216 cm^2
D 230 cm^2
E 289 cm^2
F 510 cm^2Correct.
16. What is the area of a parallelogram with height 26 cm, base 16 cm, and side length 28 cm?***need help understanding how to solve***
A 178.06 sq cm
B 122.5 sq cm
C 216 sq cm
D 416 cm^2
E 28.9 cm
F 510 cm^2You only need two measuements. They have given you an extra measurement just to make sure you know which two to multiply together.
17. What is the area of a regular octagon with a side of 6 cm? ***need help understanding how to solve***
A 178.06 sq cm
B 122.5 sq cm
C 216 sq cm
D 23 cm^2
E 173.82 cm^2
F 510 cm^2Split this into 8 triangles. The angle at the top of each triangle is 360/8 and then you need to half this to make a right angle for the tangent calculation.
18. What is the area of this polygon?***need help understanding how to solve***
You can split this polygon onto three rectangles. (see picture below) You will have to use the information to work out the length and width of each part and then add up the areas.
ls_XF = 53 mm ls_XV = 72 mm ls_VR = 16 mm
ls_FB = 31 mm ls_BT = 31 mm ls_EU = 47 mm
ls_UL = 31 mm ls_TL = 88 mm ls_DE = 16 mm
ls_RM = 70 mm ls_MC = 21 mm ls_DC = 70 mmA 8014 mm2
B7030 mm2
C6027 mm2
D5478 mm2
E 1782 mm2
F 1225 mm219. What is the area of this rectangle?***need help understanding how to solve***
Use Pythagoras to work out the height of the rectangle.
A 17.06 sq units
B60 sq units
C21.6 sq units
D53 sq units
E 28.9 sq units
F 51 sq units20. What is the area of this polygon?***need help understanding how to solve***
My picture below shows how you can split this shape into a rectangle and a triangle. You will also need to use Pythag. to get the length of the red line.
A 178 sq units
B129 sq units
C230 sq units
D240 sq units
E 219 sq units
F 206 sq unitsHope that helps
Bob
This person posted a Bible load of math questions. The other day, I was criticized for posting 4 or 5 problems.
]]>Thanks,
J
Welcome to the forum.
The diagram is in post 1. Not sure why my version isn't showing.
I'll describe it in words. Hopefully you can sort it out from that.
It's a pentagon, not regular.
Top side is 8. It turns through 90 to a length of 10. Let's call that corner A
Then it turns to a side 15. Let's call that corner B
Then it turns again to make a side of 20. Let's call that corner C.
At the other end of the 20, say point D, it turns through 90 again and heads back to the first side, getting there at point E
So we have EA = 8, AB = 10, BC = 15, CD =20 and DE we are not told.
If you continue the line of AB until the extended line meets CD, lets call that point F.
So the pentagon is split into a rectangle EAFD, and a triangle BCF. Hope that makes sense for you.
As EA is 8 and DC is 20, we can work out FC.
Then, using Pythag. you can calculate BF.
So that allows you to say how long AF (=DE) is and so work out the area of the rectangle, and the triangle by 0.5 x BF x CF.
If that all makes sense work out the two shapes and post back what you get so I can check your answers.
Bob
]]>