Bob

]]>I think you need some easier practice first. I'd be happy to go back a few steps and lead you back to this problem, with some easier ones first.

Would you like to try this?

bob

my homework needs to be done lol practice can come latter.I'm more of an IT guy but discrete math comes with my course unfortunately cant wrap my head around math at all.

]]>Would you like to try this?

bob

]]>How?

The circuit has 6 gates, 4 without the NOTs.

When I partly did the question, I had 4 of the gates done for you.

How have you got it to just 3 gates?

What happened after ( (p' OR ...) OR (...AND...) )

Bob

what exactly do i need to add to it?

]]>The circuit has 6 gates, 4 without the NOTs.

When I partly did the question, I had 4 of the gates done for you.

How have you got it to just 3 gates?

What happened after ( (p' OR ...) OR (...AND...) )

Bob

]]>That doesn't seem to require any simplification so what I said before should be fine for (a).

In your earlier thread I made some truth tables. You can do this for your function.

eg

( p ' + q ) AND p

0 1 1 0 0 0Bob

ps. If you post a function first I'll check it for you.

I have come up with, p (p + q ' ) ?

]]>In your earlier thread I made some truth tables. You can do this for your function.

eg

( p ' + q ) AND p

0 1 1 0 0 0

Bob

ps. If you post a function first I'll check it for you.

]]>hi dee93

My picture shows the three logic symbols being used here.

I think I'd work back from the output end, so you get the right brackets.

The last logic gate is an OR so start with

(... OR ...)

The top input to that OR is also an OR and the bottom input is an AND so that makes it

( (...OR...) OR (...AND...))

I'll do one more step for you.

The top input to the OR is from p through a NOT gate so now we have

( (p' OR ...) OR (...AND...) )

See if you can finish it off.

Question. Are you expected to simplify it as well?

Bob

its a two part question I have no idea how to write it.

a) What Boolean function is implemented by the circuit

) The screen shot shows that inputs of p=0 and q=0 give an outputof 1. Confirm that your Boolean function from part (a) evaluates to 1when p and q are set to 0.

My picture shows the three logic symbols being used here.

I think I'd work back from the output end, so you get the right brackets.

The last logic gate is an OR so start with

(... OR ...)

The top input to that OR is also an OR and the bottom input is an AND so that makes it

( (...OR...) OR (...AND...))

I'll do one more step for you.

The top input to the OR is from p through a NOT gate so now we have

( (p' OR ...) OR (...AND...) )

See if you can finish it off.

Question. Are you expected to simplify it as well?

Bob

]]>