If you now understand what they did then that is okay with me.
]]>Hi;
That is an extremely weird answer they give.
Sir, forgive me I should have provided how the question should be solved. the question says:
(The factorize the expression completely). I think it should be the answer if we are to factorize it, I have now comprehended it. And I can explain.
What do you say.
]]>That is an extremely weird answer they give.
]]>= (h - h)(h + h) -p(h+h)
= (h + h)(h - h - p) . The final solution provided by the book.
]]>The following is how I see it;
0-p(h+h) = (-ph - ph)
= -2ph , What do you say with my solution? The 'negative sign' was affecting the P.
]]>1) (h^2 - h^2) -p(h + h)
h^2 - h^2 = 0
There is no difference of 2 squares.
]]>It is saying, though an algebra but this type of question is called "difference of two squares".
I would provide his procedure here, which I could not quite comprehend some aspects of his procedure.
I really appreciate your enormous assistance.
Thanks.
]]>http://latex.codecogs.com/editor.php
1) (h^2 - h^2) -p(h + h)
h^2 - h^2 is 0
0 - p(h + h)
Can you do the next step?
2) X^2 + X^2 + X^2 - Y^2
X^2 + X^2 + X^2 is 3X^2
3X^2 - Y^2 we can not simplfy any further so you are done.
]]>2. X^2 + X^2 + X^2 - Y^2
Please, where can I use the mathematical items, like the (square), (plus symbol) and the others in this forum, as you have used them nicely above.
Thanks.
]]>Welcome to the forum.
This looks like what you want done:
x + x = 2x
2x + x^2 = 2x + x^2
Now x^2 - x^2 = 0.
2x + 0 = 2x
]]>x+x+x2-x2. please the two x are squared, I cannot locate them(the squares) in this forum in order to apply them conveniently on them.
]]>