If you now understand what they did then that is okay with me.

]]>Hi;

That is an extremely weird answer they give.

Sir, forgive me I should have provided how the question should be solved. the question says:

(The factorize the expression completely). I think it should be the answer if we are to factorize it, I have now comprehended it. And I can explain.

What do you say.

]]>That is an extremely weird answer they give.

]]>= (h - h)(h + h) -p(h+h)

= (h + h)(h - h - p) . The final solution provided by the book.

]]>The following is how I see it;

0-p(h+h) = (-ph - ph)

= -2ph , What do you say with my solution? The 'negative sign' was affecting the P.

]]>1) (h^2 - h^2) -p(h + h)

h^2 - h^2 = 0

There is no difference of 2 squares.

]]>It is saying, though an algebra but this type of question is called "difference of two squares".

I would provide his procedure here, which I could not quite comprehend some aspects of his procedure.

I really appreciate your enormous assistance.

Thanks.

]]>= -hp - hp.]]>

http://latex.codecogs.com/editor.php

1) (h^2 - h^2) -p(h + h)

h^2 - h^2 is 0

0 - p(h + h)

Can you do the next step?

2) X^2 + X^2 + X^2 - Y^2

X^2 + X^2 + X^2 is 3X^2

3X^2 - Y^2 we can not simplfy any further so you are done.

]]>1. (h^2 - h^2) -p(h + h).

2. X^2 + X^2 + X^2 - Y^2

Please, where can I use the mathematical items, like the (square), (plus symbol) and the others in this forum, as you have used them nicely above.

Thanks.

]]>Welcome to the forum.

This looks like what you want done:

x + x = 2x

2x + x^2 = 2x + x^2

Now x^2 - x^2 = 0.

2x + 0 = 2x

]]>x+x+x2-x2. please the two **x** are squared, I cannot locate them(the squares) in this forum in order to apply them conveniently on them.