jasminM01 wrote:jasminM01 wrote:Haha i didn't notice that until you pointed it out!

can you actually help me with the rest of it cause i can't figure it out!

so would n=20 because thats how many choices you have

and p= 4

q=1-4=3

You have 4 questions, each of which she has a 0.2 probability of answering correctly...

]]>p = 1 / 5 because that is the probability of her getting a question right.

q = 1 - 1 / 5 = 4 / 5

]]>jasminM01 wrote:Haha i didn't notice that until you pointed it out!

can you actually help me with the rest of it cause i can't figure it out!

so would n=20 because thats how many choices you have

and p= 4

q=1-4=3

The mean of the binomial distribution is np and the sd is √ (npq)

n is the number of trials

p is the probability of success.

q = 1 - p

Are you okay with this?

]]>Haha i didn't notice that until you pointed it out!

can you actually help me with the rest of it cause i can't figure it out!

]]>yea i think i can probably figure

I like the use of the word probably in a probability question. Very good!

]]>Welcome to the forum. Lifeguards save lives, firemen and paramedics do too. There is a bit more to that question, did you get it?

]]>THANK YOU ]]>

P(1 or more right ) = 369 / 625

P(none right ) = 1 - (369 / 625)

P(all right ) = 1 / 625

P(she did not get them all right) = 1 - ( 1 / 625 )

The mean of the binomial distribution is np and the sd is √ (npq)

Can you fill in the rest?

]]>