]]>But, A((3->)^G->3,(3->)^G->3) certainly is.
3^^^^^^...^^^^3 where ^ (Knuth's up arrow notation) appears Graham's number of times.
graham's number ^^^^..(graham's number ^^^....(graham's number of times)....^^^graham's number of times) .... ^^^^ graham's number
Yes, but my number is much bigger.
How? my expression surely contains more arrows than yours
]]>graham^:inf:
]]>That is not a number.
]]>