Okay, thank you. It is something to play around with.

]]>Okay, I got the paper.

For your assertion, can I read 20 / 100 to imply that 20 out of the first 100 numbers are divisible by 5 and likewise 6/36 that 6 out of the first 36 numbers are divisible by 6?

]]>I did not notice a download link for article. Are you aware of one?

]]>I notice similarities between the set of SPRS numbers (1, 3, 8, 22, 65, ...) and the set of natural numbers (1, 2, 3, 4, 5, ...). In either set,

2/4 = 1/2 of the numbers are divisible by 2.

6/18 = 1/3 of the numbers are divisible by 3.

but 3/8 of the SPRS numbers are divisible by 4 (as opposed to 2/8 = 1/4 of the natural numbers)

yet 20/100 = 1/5 of the numbers are divisible by 5.

6/36 = 1/6 of the numbers are divisible by 6.

42/294 = 1/7 of the numbers are divisible by 7.

but 3/16 of the numbers are divisible by 8.

6/54 = 1/9 of the numbers are divisible by 9.

but 3/32 of the numbers are divisible by 16.

I conjecture that 3/2^(n+1) of the SPRS numbers are divisible by 2^n for all n > 1 and 1/m of the SPRS numbers are divisible by all other numbers m not represented by 2^n.

Perhaps you find this interesting too. Thanks in advance for your comments, corrections and the like!

Sincerely,

Brian Pellerin, MSc Dalhousie