This line is the key,

How many different vote counts are possible

I think that it would be 4^50.

Every member has 4 choices. 50 members. But im not sure...

]]>There will be times when you will think you or I have found the perfect answer, I assure you these are delusions on your part. - Prof. Kingsfield

That is very good, I did not see that. That would get the same answer and there is less calculation.

]]>where n are the non-voters. There are then

.]]>the three spacers make 4 separte groups. Each group is how many is in a variable.

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this corresponds to the solution 13 + 17 + 10 + 10 = 50

]]>Your answer is correct.

]]>Not exactly, If one guy gets 20 votes there are only 30 to spread to the others.

Remember you are only voting for one position not 4.

Take 50 x's and place 3 spacers in various positions.

]]>I bet you did not do a simulation.

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