Bob

]]>-x + -9x^2 then?

]]>takes down the ^3 to ^2 which makes it 9^2(-1)

should be 9x^2(-1)

Bob

]]>27x^3(2x - 3) / 3x(3 2x)

(2x - 3) goes into (3 - 2x) -1 time. 3x goes into 27 9 times and takes down the ^3 to ^2 which makes it 9^2(-1)

-x + -9^2

Is that correct?

]]>First one:

3x^2(2x - 3)/3x(3 2x)]

So since it is (2x - 3) and (3 - 2x), it goies into it but it becomes a -1? And as for the 3x^2 and 3x, would this becomes x^2?

]]>[3(2x 3) x(2x 3)] / (2x - 3)

First fraction:

3(2x - 3)/(2x - 3)

(2x - 3) goes into (2x - 3) 1 time.

3(1)

Second fraction:

x(2x - 3)/(2x - 3)

(2x - 3) goes into (2x - 3) 1 time.

x(1)

Answer:

3 - x

correct!

#6

[x2(5x + 6) 3(5x + 6)] / (5x + 6)

First fraction:

x^2(5x + 6)/(5x + 6)

(5x + 6) goes into (5x + 6) 1 time.

x^2(1)

Second fraction:

3(5x + 6)/(5x + 6)

(5x + 6) goes into (5x + 6) 1 time.

3(1)

x^2 - 3

correct!

#7

[3x^2(2x - 3) + 27x^3(2x - 3)] / [3x(3 2x)]

This one seems a little confusing.

At this stage you can divide each part and then simplify.

(3-2x) goes into (2x-3) exactly minus 1 times

Let's get this one finished and then we can look at 8 and 9.

Bob

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I also have two more having some trouble with:

8. 15x^7 45x^5 / 3x4

19. (3x 2)(x - 4) (x - 4)(6 5x) / (4 x)(8x 1)

]]>[3(2x 3) x(2x 3)] / (2x - 3)

First fraction:

3(2x - 3)/(2x - 3)

(2x - 3) goes into (2x - 3) 1 time.

3(1)

Second fraction:

x(2x - 3)/(2x - 3)

(2x - 3) goes into (2x - 3) 1 time.

x(1)

Answer:

3 - x

#6

[x2(5x + 6) 3(5x + 6)] / (5x + 6)

First fraction:

x^2(5x + 6)/(5x + 6)

(5x + 6) goes into (5x + 6) 1 time.

x^2(1)

Second fraction:

3(5x + 6)/(5x + 6)

(5x + 6) goes into (5x + 6) 1 time.

3(1)

x^2 - 3

#7

[3x^2(2x - 3) + 27x^3(2x - 3)] / [3x(3 2x)]

This one seems a little confusing.

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I also have two more having some trouble with:

8. 15x^7 45x^5 / 3x4

19. (3x 2)(x - 4) (x - 4)(6 5x) / (4 x)(8x 1)

]]>5, 6 and 7 are very similar to 4, so have a go and post your answers.

Bob

]]>Correct! Very good!

]]>Second part of the equation:

3(x 1)/( x - 1)

Same way, (x - 1) goes into (x - 1) 1 time making it 3(1).

So now the equation is:

2 + 3 and the final answer will be 5.

Am I correct?

]]>Bob

]]>2(x 1)/(x - 1) + 3(x 1)/( x - 1)

For the first fraction:

so (x - 1) goes into (x - 1) one time making it 2(1). Now I want to stop right here and make sure that I'm doing this right.

Q4. Same method:

Bob

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