Using: a³ + b³ + c³ - 1 is divisible by "p"
Perhaps only a³ + b³ can be divisible by p, so subtracting 1 requires adding 1, and that is the c³ term
Also:
a + b + c - 1 = p
( a³ + b³ + c³ - 1 ) / ( a + b + c - 1 ) = whole number
That is as far as I have got, and I have to go do something else now.
]]>