Is sometimes true and sometimes false.
Is sometimes true and sometimes false.
Please post the original problem and maybe something can be done.
]]>Do the other ones work too? This is bad news for me, means I messed up somewhere. I just tried to input e.g. 0.9 =p and 0.9 = q and it did not work, you are correct. darn!!
]]>Is sometimes true and sometimes false.
]]>It is not the case, here p + (1-p) = 1, and q + (1-q) = 1.
(1-q) and (1-p) don't feature here in that form because I had to use them to derive the given inequalities. So I guess here, p+(1-p)+q+(1-q)=2 ? But that cancel's out to 2=2 so i guess is not useful...
I look forward to your reply!
]]>When you use the variables p and q and mention the word probability it is standard for the relationship between p and q to be p+q=1. That is what confused me. Is this the case?
Also p+q>1 +(pq)/2 is sometimes true and sometimes false.
]]>But why does p+q = 1 ?
If p = 0.2 (so 1-p=0.8) and q=0.3 (so 1-q = 0.7) then p+q = 0.5 whilst still being viable given restrictions on p and q... ?
]]>p+q > 1+ (pq)/2 -
What comes after the minus sign in all three problems?
]]>Ok, completely new assumptions. Discard the above. I didn't include r.
So, 0<p<1 so that (1-p) + p = 1. (Probability)
Also, 0<q<1 so that (1-q) + q = 1.
Now;
1. p+q > 1+ (pq)/2 - (I have cancelled this down to this, why can this NOT work? I can't understand the intuition / maths)
2. p+q > 6/15 + 2pq - (I have cancelled this down to this, why can this NOT work? I can't understand the intuition / maths)
3. 1 > p + q + pq - (I have cancelled this down to this, why can this NOT work? I can't understand the intuition / maths)
Thank you!!
]]>Ok, 0<pi<1, i=1,2,3,4 . BUT the SUM =1, so Sum p1+p2+p3+p4 =1. But none of them can be 0 or 1, all inbetween whilst summing to one.
Now, given this.... I want to understand WHY these inequalities CANNOT hold:
1. 9(p1) > 6(p1) + 6(p4)
2. 9(p2) + 9(p3) > 6(p1) + 6(p4)
3. 9(p4) > 6(p1) + 6(p4)
Treat all of these seperately! I don't know if this is correct or not, basically I think all is correct until this point, but this is the checking part...i.e. if these DO NOT hold, I am correct. Thank you I really cannot wait until I see the response!!!!
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