Well actually Saxon wasn't a 100% mathematician, I think he was an engineer and computer scientist, and a very good teacher. He wrote mathbooks for grades 1 though 12, including algebra 1, 2, trig and calculus. He also wrote books on other subjects like phonics. (yuck!) Saxon's philosophy was that math is not difficult, math is differant, and that people often call things that are unfamiliar to them, difficult, and things that are familiar easy. Time and practice is required for things that are differant to become things that are familiar and thus, easy. This philosophy is the basis for saxons teaching. Where some mathbooks would try to teach all the aspects of a topic in one lesson, saxon presents each topic little by little. Begining with the simplelest problems of that type and saving the more advanced problems for a later lesson. Each short lesson has 30 practice problems to do before moving on. This ensures you become familiar with each concept making comprehension of the more advanced problems easy since you have a solid foundation on the previous topics. "An Incremental Development" is written under the title of each saxon book. I taught myself algebra 1, 2 trigonometry with these books and am now working on calculus. Very good books, I highly reccomend them to anyone.

]]>If you replaced your '1, 1, 2, 4, 7, 11' with any 6 numbers, I could crank out an nth term that would most probably involve n^5 and lots of big fractions, but the progression would nonetheless exist. Who's Saxon?

]]>0, 1, 2, 3, 4 <-- Take differences

1, 1, 1, 1 <-- Take 2nd differences

The 2nd differences are all the same, so put 1/2! = 1/2 as the n² term. Then subtract the values that you get from doing n²/2 and do it again.

1-0.5, 1-2, 2-4.5, 4-8, 7-12.5, 11-18

0.5, -1, -2.5, -4, -5.5, -7

-1.5, -1.5, -1.5, -1.5, -1.5 <-- Take differences

The differences are all the same, so put -1.5/1! = -1.5 as the n term. Then subtract the values that you get from doing n²/2 - 1.5n and do it again.

0.5+1.5, -1+3, -2.5+4.5, -4+6, -5.5+7.5, -7+9

2 , 2 , 2 , 2 , 2 , 2

The values are all 2, so that's the last part of your sequence.

Your overall sequence is therefore n²/2 - 3n/2 + 2.

To find the next term, substitute n = 7 into the sequence to get 49/2 - 21/2 + 2 = 16.

You could have got that by observation and guessing anyway, but that's a proper answer with working and stuff.

]]>Find the next term in a sequence who's first six terms are 1,1,2,4,7,11.

At first I thought it was an arithmatic sequance, but 1 + d = 1, 1 + 2d = 2, 1 + 3d = 4 etc all yield differant values of d so there is no common differance.

So I thought perhaps it was a geometric progression. If that were the case, then dividing any term by the previous term would give us the common ratio. But again, it doesn't work. 1/1 = 1, 2/1 = 2, etc.

After some guess work, I noticed the pattern 1, (1 + 0), (1 + 1), (1 + 3), (1 + 6), (1 + 10)

if you look at the numbers 0 ,1, 3, 6, 10.

1 is one greater then 0. 3 is two greater then 1. 6 is three greater then 3. 10 is four greater then 6. The answer to the problem is consistant with this sequence, but I've never seen a sequence like this. It does not appear to be arithmatic as it does not have a common differance, and it does not appear to be geometric as there is no common ratio.

So what is it and how would I solve it without guessing?

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