So not monotonic.

Ummm ... if you have to say more, you could say it IS monotonic for negative x. You could also do the derivative and find the turning points.

f(x) = 30x^9 + 2x^8 + 300x^7 - (17/2)x^6 - x^5 + 3x^4 +973x^3 - 200x^2 + x + 1

f'(x) = 270x^8 + 16x^7 + 2100x^6 - 51x^5 - 5x^4 + 12x^3 +2919x^2 - 400x + 1

Now solve for f'(x)=0, which I can't do because it has way too many terms, so that was fairly useless.

]]>Note the scale on the axes.

]]>But a more formal definition says it is monotonic if it is either always increasing in x (or always decreasing in x), in other words always a general up-slope (or always a general down-slope).

So monotonic can't have humps and bumps

Example: y = 2x

(I think FLAT also qualifies, so y=2 would work, and they say "strict" if it doesn't qualify)

Is your polynomial monotonic? Plot it in Excel and see. (Also you may be able to do a derivative and find if the slope ever changes sign ... I think that might work, but better read up on it first!)

]]>Answer: We will expand the polynomial into longhand form:

30xxxxxxxxx+2xxxxxxxx+300xxxxxxx-(17/2)xxxxxx-xxxxx+3xxxx+973xxx-200xx+x+1.

As you can see, f(x) is highly monotonous. Even the best of orators would be hard pressed to read it without slipping into a monotone. Note also that the monotonicity of f decreases as it goes along; the monotonous x's are broken up more frequently by other stuff, making it far more...polytonous?

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