Hi,benice;

I review the sites and infer that the earliest one is before 2011-07-29 09:35:26 (+8). But the site you gave just show "9 months ago", when the equation was flooding, so I don't know whether that is the original one.

The original post was submitted on 28 Jul 2011. (Look at the upper right corner of the comment page.)

Sumasoltin wrote:

We tried to plot it, only to found it abused "sqrt" so there is no plot. I tried to correct but gave up later because of the complex numbers (complex, not "i").

Plot each component separately:

f1(x,y) = ((x/7)^2) * sqrt( sign(abs(x)-3) ) + ((y/3)^2) * sqrt( sign(y+3*sqrt(33)/7) ) - 1

f2(x,y) = abs(x/2) - ((3*sqrt(33)-7)/112)*(x^2) - 3 + sqrt(1 - (abs(abs(x)-2)-1)^2) - y

f3(x,y) = 9*sqrt( sign((1-abs(x))*(abs(x)-0.75)) ) - 8*abs(x) - y

f4(x,y) = 3*abs(x) + 0.75*sqrt( sign((0.75-abs(x))*(abs(x)-0.5)) ) - y

f5(x,y) = 2.25*sqrt( sign((0.5-abs(x))*(abs(x)+0.5)) ) - y

f6(x,y) = 6*sqrt(10)/7 + (1.5-0.5*abs(x))*sqrt(sign(abs(x)-1)) - 6*(sqrt(10)/14)*sqrt(4-(abs(x)-1)^2) - y

bobbym wrote:The Batman equation?

Hi bobbym,

The original post is here.

Hi,benice;

I review the sites and infer that the earliest one is before 2011-07-29 09:35:26 (+8). But the site you gave just show "9 months ago", when the equation was flooding, so I don't know whether that is the original one.

We tried to plot it, only to found it abused "sqrt" so there is no plot. I tried to correct but gave up later because of the complex numbers (complex, not "i").

Thanks for coming over. Thanks for the link too.

]]>The Batman equation?

Hi bobbym,

The original post is here: http://redd.it/j2qjc.

]]>Well , math is a subject created by God, and you can make any thing into equations if you want. Pencils, flowers, waves, boats, mountains, bra and math(:P),and even a girl !]]>

Tip:Thanksgiving Days]]>

I did use k instead of 5,but a known number looks better.]]>

"Who found this?",I search it on Google and finally I learned it was Siehe Beutel.But how he found this?

We chosed Archimedes spiral: x²+y²=arc tan²(y/x)

we find that "tan x" is simillar to "x³",so we got

(x²+y²)³=(y/x)²

we find heart isn't a symmetrical shape,so we change "y²" by "y³"

As x becomes larger,the difference between "tan x" and "x³" becomes larger,so we plus "x⁴"

Aha~just a joke ! Maybe following can be turth.

He used a simple ellipse "x²+y²-xy=1".

We transform it to "x²+y²-1=|x|y".

NO ABS ! We get "(x²+y²-1)²=x²y²".

But now we lose the relation of that "x²+y²-1" is the same to "y" in "±" (I can't convey in proper way)

So we try the equation "(a²x²+b²y²-1)^(2k+m)=(by)^m*(abxy)^2k"

when a、b→1,there is the equation "

(x²+y²-1)^m=y^m"

So we have "|x|^m=((x²+y²-1)/y)^m=1"

Compare plots of "x²+y²-xy=1" and "x²+y²-y=1",we find only when x∈[-1/2,1/2] their difference become obvious,so m→0.

We make m=1，so k→+∞.

By trying,due to the equation's interval,when k=1 we get such a beautiful plot : (x²+y²-1)³=x²y³]]>