<![CDATA[Math Is Fun Forum / Tricky Puzzle]]>2005-10-14T00:16:28ZFluxBBhttp://www.mathisfunforum.com/viewtopic.php?id=1724<![CDATA[Re: Tricky Puzzle]]>I got that answer right before i checked the posts. haha]]>http://www.mathisfunforum.com/profile.php?id=16032005-10-14T00:16:28Zhttp://www.mathisfunforum.com/viewtopic.php?pid=15607#p15607<![CDATA[Re: Tricky Puzzle]]>Let the pentagon be ABCDE AB is 7,2,10 BC is 10,1,8 CD is 8,5,6 DE is 6,4,9 and EA is 9,3,7

The total is 19 on all sides!

]]>http://www.mathisfunforum.com/profile.php?id=6822005-10-13T09:57:39Zhttp://www.mathisfunforum.com/viewtopic.php?pid=15576#p15576<![CDATA[Re: Tricky Puzzle]]>Would you have an illustration of this?

You can either link to one, or upload one (via "Post Reply")

]]>http://www.mathisfunforum.com/profile.php?id=22005-10-13T07:34:57Zhttp://www.mathisfunforum.com/viewtopic.php?pid=15563#p15563<![CDATA[Tricky Puzzle]]>You have a pentagon with three circles on each side. One on each corner and one in the middle. With a total of 10 circles. You need to put in a number 1-10 into each circle and you cant reuse any numbers. Each side needs to add up to the same sum. I read somewhere that the 4 possibilites make the sums of 14, 16, 17, 19. I solved the one for 14 but cant do the others. Any answers would be appreciated.]]>http://www.mathisfunforum.com/profile.php?id=16032005-10-13T00:22:45Zhttp://www.mathisfunforum.com/viewtopic.php?pid=15534#p15534