2005-10-05T04:57:53ZFluxBBhttp://www.mathisfunforum.com/viewtopic.php?id=1676Given two points, the equation of the line joining the points is (y-y1)/(y2-y1) = (x-x1)/(x2-x1) Substituting y1 = 5, y2 = -1, x1 = 3 and x2 = -3, the equation of the line is x-y+2 = 0, The slope of this line m=(y2-y1)/(x2-x1), i.e., m = 1. The slope of a line perpendicular to this line would be -1 (Because, if two lines are perpendicular, the product of their slopes is -1). The midpoint of U(3,5) and V(-3, -1) is given by [(x1+x2)/2, (y1+y2)/2] Therefore, the midpoint of the line UV is (0,2). The equation of a line of given slope passing through a given point is (y-y1) = m(x-x1) We know, m=-1 for the perpendicular line. Therefore, the equation of the perpendicular bisector is (y-2) = -1(x-0) or x+y-2 = 0 Substitute the x and y coordinates of point W(2,-1) in this equation. We see that it does not satisfy the equation. Therefore, the point does not lie on the perpendicular bisector.]]>http://www.mathisfunforum.com/profile.php?id=6822005-10-05T04:57:53Zhttp://www.mathisfunforum.com/viewtopic.php?pid=15000#p15000Determine whether the point W(2,-1) lies on the perpendicular bisector of line segment UV, endpoints U(3,5) and V(-3,-1). Explain and justify your answer.
I cant figure it out, if someone could, it would be a pleasure!!!!!