<![CDATA[Math Is Fun Forum / needed: formula for curved trajectory to hit specific target]]> 2013-02-20T11:32:34Z FluxBB http://www.mathisfunforum.com/viewtopic.php?id=1673 <![CDATA[Re: needed: formula for curved trajectory to hit specific target]]> Hi;

Those are two parametric equations. We called them that becuse they are both expressed in terms of t.

To graph them in that form you will need a parametric plotter.

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http://www.mathisfunforum.com/profile.php?id=33790 2013-02-20T11:32:34Z http://www.mathisfunforum.com/viewtopic.php?pid=254348#p254348
<![CDATA[Re: needed: formula for curved trajectory to hit specific target]]> helllo

velocity is 10 m/s

at 10 m/s it travels approximately 489 m before touching the ground, and this is quite a large distance (non practical )

I think there is no drag , that is why the length of projectile is so long.

Could you help me inserting drag in this formula
x = vt cos ?
y = vt sin ? - ½ g t²

here you can find some formula for drag, http://en.wikipedia.org/wiki/Drag_%28physics%29

and let me tell you i am little dumb in mathematics Thanks

EDIT : I want to draw the path of projectile.

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http://www.mathisfunforum.com/profile.php?id=198541 2013-02-20T06:19:54Z http://www.mathisfunforum.com/viewtopic.php?pid=254341#p254341
<![CDATA[Re: needed: formula for curved trajectory to hit specific target]]> Hi;

with a initial velocity of 10

10 what?

angle it goes to 489 m

Maximum height? Distance? Arc length? 489 m of what?

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http://www.mathisfunforum.com/profile.php?id=33790 2013-02-20T02:57:06Z http://www.mathisfunforum.com/viewtopic.php?pid=254338#p254338
<![CDATA[Re: needed: formula for curved trajectory to hit specific target]]>

sorry for reviving this thread again smile

here in this formula
x = vt cos ?
y = vt sin ? - ½ g t²

v (velocity) is the initial velocity or a constant velocity ? will velocity changes with time ? or it remains constant ?

In my last post i ask this.
here is the projectile i get using this formula http://imgur.com/axCKwsP

Don't you guys think for 60* angle this is Quite a large projectile ?
with a initial velocity of 10 and 60* angle it goes to 489 m, let me tell you i am decreasing the initial velocity and increasing time by 0.1 at each step.
I dont know i am doing it in right way or not can any one suggest me any thing ?

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http://www.mathisfunforum.com/profile.php?id=198541 2013-02-19T13:22:01Z http://www.mathisfunforum.com/viewtopic.php?pid=254308#p254308
<![CDATA[Re: needed: formula for curved trajectory to hit specific target]]> sorry for reviving this thread again here in this formula
x = vt cos θ
y = vt sin θ - ½ g t²

v (velocity) is the initial velocity or a constant velocity ? will velocity changes with time ? or it remains constant ?

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2013-02-18T18:52:27Z http://www.mathisfunforum.com/viewtopic.php?pid=254255#p254255
<![CDATA[Re: needed: formula for curved trajectory to hit specific target]]> Hi roi187;

Your are welcome and welcome to the forum!

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http://www.mathisfunforum.com/profile.php?id=33790 2011-08-29T17:06:12Z http://www.mathisfunforum.com/viewtopic.php?pid=187851#p187851
<![CDATA[Re: needed: formula for curved trajectory to hit specific target]]> bobbym wrote:

Hi;

To get rid of the 1 / 2 you multiply by 2, because 2 * 1 / 2 = 1

OK I understand now. Thank you very much! ]]>
2011-08-29T17:04:47Z http://www.mathisfunforum.com/viewtopic.php?pid=187850#p187850
<![CDATA[Re: needed: formula for curved trajectory to hit specific target]]> Hi;

To get rid of the 1 / 2 you multiply by 2, because 2 * 1 / 2 = 1

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http://www.mathisfunforum.com/profile.php?id=33790 2011-08-29T16:52:26Z http://www.mathisfunforum.com/viewtopic.php?pid=187848#p187848
<![CDATA[Re: needed: formula for curved trajectory to hit specific target]]> bobbym wrote:

Hi;

I don't get why 499.6 was divided into 1/2

Both sides were multiplied by -2

This isn't clear to me a bit; why we multiplied both sides by 2? Is it because we had two T variables there has a coefficient of 2? Sorry, my algebra is really that rusted. ]]>
2011-08-29T16:46:26Z http://www.mathisfunforum.com/viewtopic.php?pid=187847#p187847
<![CDATA[Re: needed: formula for curved trajectory to hit specific target]]> Hi;

I don't get why 499.6 was divided into 1/2

Both sides were multiplied by -2 and some rounding was done

-499.6 * -2 ≈ 999

Then both sides were divided by 9.81 and some rounding done again to get.

100 = t^2

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http://www.mathisfunforum.com/profile.php?id=33790 2011-08-29T16:39:19Z http://www.mathisfunforum.com/viewtopic.php?pid=187845#p187845
<![CDATA[Re: needed: formula for curved trajectory to hit specific target]]> MathsIsFun wrote:

300 = vt (0.5)
20 = vt (0.866) - ½ g t²

the first equation gives us: vt = 300 / 0.5 = 600

put that into the second equation: 20 = 600 x 0.866 - ½ g t²
rearrange: 20 - 600 x 0.866 = - ½ g t²
simplify: 499.6 = ½ g t²
simplify: 999 = g t²
simplify: 999 = t²
solve: t = ± 10 seconds

Hi, sorry for reviving an ANCIENT thread... I have problems understanding the processes done in this equation.
I don't get why 499.6 was divided into 1/2 and g value is omitted? And lastly, how did sqrt 999 became 9.999 or 10?

Once again I am sorry, but once I get all the answers It'll help me tons.

Thanks in advance ]]>
2011-08-29T15:55:17Z http://www.mathisfunforum.com/viewtopic.php?pid=187844#p187844
<![CDATA[Re: needed: formula for curved trajectory to hit specific target]]> hey there, sorry for bumbing an old thread:

I have the following values in my 3d world:

- my current x & y angle
- the distance in meters to the target
- the height offset in meters
- the velocity of the projectile m/s

I need to calculate the angle y offset I need to add to my current angle y so that the missile will hit the target.

I have tried to make a formula but im not good at maths, Im getting confused with the above formulas too because they have t (time), but since my projectile hasn't been fired i won't have time.

Thanks for any help!

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2007-02-03T00:58:02Z http://www.mathisfunforum.com/viewtopic.php?pid=58318#p58318
<![CDATA[Re: needed: formula for curved trajectory to hit specific target]]> can i play?>?>?>

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http://www.mathisfunforum.com/profile.php?id=3915 2006-05-19T01:43:31Z http://www.mathisfunforum.com/viewtopic.php?pid=35032#p35032
<![CDATA[Re: needed: formula for curved trajectory to hit specific target]]> Thanks guys for all your help. The equations work and I will post a link when the game is launched.

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http://www.mathisfunforum.com/profile.php?id=1493 2005-10-09T11:01:01Z http://www.mathisfunforum.com/viewtopic.php?pid=15330#p15330
<![CDATA[Re: needed: formula for curved trajectory to hit specific target]]> Both of the equations listed here are helpful but the best equation to use is combining the two equations;

x = vt cos θ
y = vt sin θ - ½ g t²

From the first one, get t on its own and sub it into the second one. You don't need to take into account what the time is for your problem. The math would get a bit ugly on this, but after simplifying you should get;

y = x tanθ - gx²(1+ tan² θ)
2v²

So if you need to hit a target x metres away and y metres high, you can work out the angle needed for the velocity you launch it at. Or if you launch it at an angle theta, velocity v and you want to know how far away the projectile is when it is one meter high...

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http://www.mathisfunforum.com/profile.php?id=1477 2005-10-05T17:45:58Z http://www.mathisfunforum.com/viewtopic.php?pid=15038#p15038