<![CDATA[Math Is Fun Forum / Help please]]>2005-10-02T20:50:31ZFluxBBhttp://www.mathisfunforum.com/viewtopic.php?id=1651<![CDATA[Re: Help please]]>thank you! ]]>2005-10-02T20:50:31Zhttp://www.mathisfunforum.com/viewtopic.php?pid=14905#p14905<![CDATA[Re: Help please]]>The -2 stays on the top (numerator). The -2^-3 goes to the top as -2^3. So now you have -2 times -2^3. Then -2^3 is -8 because -2 times -2 times -2 is -8. So that times -2 is 16. So add 16 in the middle term of your entire problem.]]>http://www.mathisfunforum.com/profile.php?id=11082005-09-27T17:10:46Zhttp://www.mathisfunforum.com/viewtopic.php?pid=14799#p14799<![CDATA[Help please]]>Hi, I need some help on an algebra problem, it's -2/-2^-3 (if that makes any sense). I know that I have to flip it over, but what's confusing me is that the first number is a 2 and I'm not sure how that will affect it. The entire problem is -3^-2-2/-2^-3-2^0, and the book says that the answer is 14 8/9.